In the given AC circuit, when switch S is at position 1, the source emf leads current by π6,Now, if the switch is at position 2, then

source emf leads current by π 3

source emf leads current by π 3

source emf leads current by π 4

current leads source emf by π 4

current leads source emf by π 3

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In the given AC circuit, when switch S is at position 1, the source emf leads current by $\frac{π}{6}$ ,Now, if the switch is at position 2, then

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source emf leads current by $\frac{π}{3}$

source emf leads current by $\frac{π}{4}$

current leads source emf by $\frac{π}{4}$

current leads source emf by $\frac{π}{3}$

answer is A.

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$\begin{array}{l} ωL / R = \tan π / 6 \Rightarrow R = 3 Ω \\ \tan ϕ = 1 / ωCR = 1 \\ \Rightarrow ϕ = π / 4, leading P.D. \end{array}$

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