In the given anions, the weakest Bronsted base is

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${ClO}_{4}^{-}$

${ClO}_{2}^{-}$

${ClO}_{3}^{-}$

${ClO}^{-}$

answer is A.

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Detailed Solution

Strongest acid amongst $HClO, {HClO}_{2}, {HClO}_{3}$ and ${HClO}_{4}$ is ${HClO}_{4}$ . Hence, the conjugate base ${ClO}_{4}^{-}$ will be the weakest.

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