In the given Boolean expression, Y=A·B+B·A, if A=1, B=1 then Y will be

Y=A·B+B·AGiven: A=1 , B=1⇒Y=1·1+1·1=1·0+1·0=0+0=0

In the given Boolean expression, Y=A·B+B·A, if A=1, B=1 then Y will be

Y=A·B+B·AGiven: A=1 , B=1⇒Y=1·1+1·1=1·0+1·0=0+0=0

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In the given Boolean expression, $Y = A \cdot B + B \cdot A$ , if A=1, B=1 then Y will be

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$Y = A \cdot B + B \cdot A$

Given: $A = 1, B = 1$

$\Rightarrow Y = 1 \cdot 1 + 1 \cdot 1 = 1 \cdot 0 + 1 \cdot 0 = 0 + 0 = 0$

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In the given Boolean expression, Y=A·B+B·A, if A=1, B=1 then Y will be

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In the given Boolean expression, $Y = A \cdot B + B \cdot A$ , if A=1, B=1 then Y will be