In the given circuit,${\mathrm{C}}_1=2\mathrm{\mu F}$,${\mathrm{C}}_2=0.2\mathrm{\mu F}$,${\mathrm{C}}_3=2\mathrm{\mu F}$,${\mathrm{C}}_4=4\mathrm{\mu F}$,${\mathrm{C}}_5=2\mathrm{\mu F}$,${\mathrm{C}}_6=2\mathrm{\mu F}$, The charge stored on capacitor ${\mathrm{C}}_4$ is ______$\mathrm{\mu C}$.

Equivalent capacitance = $0.5 \mathrm{\mu F}$

 Charge supplied by the battery,  $\mathrm{q}=10\times \frac{1}{2}=5\mathrm{\mu C}$

The total charge coming out of the battery will be distributed into C₂ and the series combination of the C₃ , C₄ , C₅.
$\therefore$Charge on ${\mathrm{C}}_4=\frac{\mathrm{q}}{1}\times \frac{(\mathrm{effective} \mathrm{cap} \mathrm{of} {\mathrm{C}}_3+{\mathrm{C}}_4+{\mathrm{C}}_5)}{\left(\mathrm{effective} \mathrm{cap} \mathrm{of} {\mathrm{C}}_3+{\mathrm{C}}_4+{\mathrm{C}}_5+ \mathrm{cap} \mathrm{of} {\mathrm{C}}_2\right)}=4\mathrm{\mu c}$