In the given circuit (Figure), the switch is closed at t = 0. Choose the correct answers.

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Current in the inductor when the circuit reaches the steady state is 4 A.

The time constant of the circuit after closing S is 555.55s.

The charge stored in the capacitor in steady state is 1.2 mC.

The net change in flux in the inductor is 1.5 Wb.

answer is A, B.

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Detailed Solution

$At = 0, I_{L} = \frac{6}{6} = 1 A$

$At t >> 0, I_{L} = \frac{12}{3} = 4 A$

$∴ | ϕ | = L (i_{f} - i_{i}) = 500 \times 10^{- 3} \times 3 = 1 .5 Wb$

$∴$ (1) and (2) are the correct choices.

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