In the given circuit (figure), when key K is open, reading of ammeter is I. Now key K is closed, then the correct statement is 

Reading of ammeter will not change

If  $IR<{\epsilon }_1,$ reading of the ammeter is greater than I

If ${\epsilon }_1<IR,$ reading of the ammeter is less than I

If ${\epsilon }_1<2IR,$ reading of the ammeter will be zero