In the given circuit, if the voltmeter is ideal its reading is V1 volts. If the voltmeter has a resistance of 100 $Ω$ the reading is $V_{2} . Then |V_{1} - V_{2}|$ is equal to:-

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0.3volts.

0.2volts

Zero

0.1volts

answer is D.

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Detailed Solution

$V_{1} = \frac{10}{4 + 4} \times 4 volts = 5 volt V_{2} = \frac{10 \times \frac{100 \times 4}{100 + 4}}{4 + \frac{100 \times 4}{100 + 4}} = 4 .9 volts ∴ |V_{1} - V_{2}| = 0 .1 volt$

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