In the given circuit, of $+ 80 μ C$ is given to the upper plate of the $4 μ F$ capacitor. Then in the steady state, the charge on the upper plate of the $3 μ F$ capacitor is ____ $μ C$

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answer is 48.

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The total charge on plate $A$ will be $80 μ C$ .
$2 μ F$ and $3 μ F$ capacitors are in parallel. Therefore, $C_{e q} = 2 + 3 = 5 μ F$
Charge on capacitor of $3 μ F$ capacitance $q = \frac{3}{5} \times 80 = 48 μ C$

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