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In the given circuit, rms value of current $(I_{r m s})$ through the resistor R is :

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$\frac{1}{2} A$

20 A

$2 \sqrt{2} A$

answer is A.

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Detailed Solution

$z = \sqrt{100^{2} + {(200 - 100)}^{2}}$

$= 100 \sqrt{2} Ω$

$i_{r m s} = \frac{V_{r m s}}{z} = \frac{200 \sqrt{2}}{100 \sqrt{2}}$

$= 2 A$

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