In the given circuit, the potential difference across the capacitor is 12 V at steady state. Each resistance is of $3 Ω$ . The cell is ideal. The emf of the cell is given by $E$ volt. Find value of $\frac{E}{3}$ .

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answer is 5.

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Detailed Solution

In steady our circuit become

So that $V_{AB} = 12$
$R_{eq} = R + \frac{2 R}{3} = \frac{5 R}{3}$

$i = \frac{3 E}{5 R} i = \frac{R}{3 R} \times \frac{3 E}{5 R} = \frac{E}{5 R} \Rightarrow 12 - \frac{E}{5 R} \times R - \frac{3 E}{5 R} R = 0 12 = \frac{4 E}{5} \Rightarrow E = 15 \frac{E}{3} = 5$

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