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In the given circuit the reading of the ammeter is [[1]] $A$ and the reading of voltmeter is [[2]] $V$ if the key is closed.

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Detailed Solution

In the given circuit, the reading of the ammeter and voltmeter would be

0.24 A

and

2.88 V

respectively.
Since all the resistors are connected in series combination, the equivalent resistance is given by the sum of individual resistances as follows

R = {R_{1} + R}_{2} + R_{3}

On substituting the values of resistors, we get the resistance as

R = 5 + 8 + 12

\Rightarrow R = 25 Ω

It is known that the ammeter is used to measure the current flowing through the circuit. Hence, the reading of the ammeter is

I = \frac{V}{R}

\Rightarrow I = \frac{6}{25}

\Rightarrow I = 0.24 A

It is also known that the voltmeter is used to measure the potential difference between two points. Hence, the reading across

12 Ω

resistor is,

V = IR

\Rightarrow V = 0.24 \times 12

\Rightarrow I = 2.88 V

Hence, the ammeter reading is

0.24 A

and the voltmeter reading is

2.88 V

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