In the given circuit the value of current $I_Z$ (in m A) will be 

 

Since the pressure and volume decreased, from PV = nRT, the temperature must decrease. This means that the internal energy change is negative since the internal energy depends on the temperature for an ideal gas. Since the volume decreases, the work done on the gas by the surroundings is positive (force is directed inward on gas and movable piston of container moves inward). Finally, from the First Law of Thermodynamics, $\Delta U=Q+W\Rightarrow (-)=Q+(+).$ This means that the quantity of heat in this  process will have to be negative $Q=(-)+(-)=(-)$