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Q.

In the given circuit, which is a part of closed circuit, find the currents  
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a

1 A. 0.6 A

b

0.4 A, 0.6 A

c

 0.6 A, 0.4 A

d

1 A, 0.4 A

answer is C.

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Detailed Solution

Let the potential at O be V
From Kirchoff’s junction law
i = i1+i2
30V10=V1220+V230
180 – 6V = 5V – 40
11V = 220
V = 20 volt
i1=V1220=820=0.4 A
i2=1830=0.6 A

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