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In the given diagram, pulley is frictionless and massless. Both the springs are having same force constant 10 N/m. Initially, with the string attached to the grounds, the total system is at rest. Now, if the left spring is cut, then immediately after cutting the left spring $[g = 10 m / s^{2}]$

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Tension in the string connecting 6kg and 9 kg blocks is 120N

Tension in the string connected to ground is 40N

Acceleration of 5kg block is zero

Acceleration of 6kg block is $\frac{10}{3} m / s^{2}$

answer is B, C, D.

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Detailed Solution

Just after cutting the left spring, for 5kg block,
$a_{5 kg} = g ↓$
For (9kg + 6kg) system
$\begin{array}{l} 140 - T = 6 a \\ T - 90 = 9 a \\ a = \frac{50}{15} = \frac{10}{3} m / s^{2} \end{array}$
$T = 120 N$

$For 6 kg, 60 + kx - T = 6 a \Rightarrow kx = 80 N$
For 4kg , $80 = 40 + T_{1}$
$T_{1} = 40 N$

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