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Q.

In the given figure, ACB  =90° and CDAB  . State if the given condition true or false “ C B 2 C A 2 = BD AD  ”.


Question Image

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a

False

b

True 

answer is B.

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Detailed Solution

It is given that, ∠ACB=90° and CD⊥AB.
Question ImageIf a perpendicular is drawn from the right angle's vertex to the hypotenuse, the triangle on both sides of the perpendicular is similar to the whole triangle and to each other.
We can observe from the figure that in triangle ACD and ABC,
∠ADC=∠ACB(90°)
∠CAD=∠CAB(same)
Triangle ACD ΔABC by AA criterion.
In triangle BCD and BAC
∠BDC=∠BCA(90°)
∠CBD=∠CBA(same)
Hence, the triangle BCDBAC by AA criterion.
We can observe from the figure that, ΔACD~ΔABC and ΔBCD~ΔBAC with AA similarity criterion.
Since, corresponding sides of similar triangles are proportional, we can write that,
  ΔACDΔABC AC AB = AD AC A C 2 =AB×AD.(1)  ΔBCDΔBAC BC BA = BD BC B C 2 =BA×BD(2)  
Dividing (2) by (1),
B C 2 A C 2 = BA×BD AB×AD B C 2 A C 2 = BD AD  
Hence the given statement is true i.e., Question Image.
Hence, the correct option is 2.
 
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In the given figure, ∠ACB  =90° and CD⊥AB  . State if the given condition true or false “ C B 2 C A 2 = BD AD  ”.