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Q.

In the given figure a particle of charge q, mass m & velocity $V_{0}$ enters in a field $B_{0}$ . Find the value of L

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a

$\frac{m V_{0}}{3 q B_{0}}$

b

$\frac{m V_{0}}{2 q B_{0}}$

c

$\frac{2 m V_{0}}{q B_{0}}$

d

$\frac{m V_{0}}{q B_{0}}$

answer is B.

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Detailed Solution

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Question Image

$L = R \sin θ = \frac{m V}{q B} \sin θ = \frac{m V}{q B} = (θ = 30^{\circ})$

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