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Q.

In the given figure, ABCD is a parallelogram in which AB is extended to E such that BE=AB  . Find the relation between OB and BC.


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a

OB= 2 3 BC  

b

OB= 1 3 BC  

c

OB= 1 2 BC  

d

OB= 2 5 BC   

answer is C.

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Detailed Solution

Given is a parallelogram in which AB is extended to E such that BE=AB  .
Consider parallelogram ABCD.                           Question ImageFrom, ΔODC   and ΔOEB  ,
COD=BOE          ... (vertically opposite angles)
OCD=OBE          ... (alternate angles with transversal BC)
DC=AB                     … (opposite sides of parallelogram)
BE=AB                      ...(given)
Therefore, DC=BE  .
Apply the AAS criterion, ΔODCΔOEB  .
OC = OB                                 ...by CPCT.
Since, BC = OC + OB.
Therefore, ED bisects BC which means O is the midpoint of BC.
Therefore, OB= 1 2 BC  .
Hence, option 3 is the correct choice.
 
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