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Q.

In the given figure, AD   divides BAC   in the ratio 1:3   and AD=DB  . Then the value of x   is


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a

45°  

b

90°  

c

115°  

d

75°   

answer is B.

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Detailed Solution


It is given that AD   divides BAC   which is in the ratio of 1:3  .
We have to find the value of x  .
Consider BE   as a straight line,
So, BAC+CAE= 180 °  .
BAC+108°=180°  
BAC=180°108°  
=72°  
Divide 72°   in the ratio of 1:3  , so that,
a+3a=72°  
4a=72°  
a= 72° 4  
=18°  
BAD=18°   and,
DAC=3(18°) =54°  
Consider the triangle ABC  , since sum of the angles of the triangle is 180°  .
A + B+ C =  180 °  
72 °  +  18 °  + x=  180 °  
90°+x=180°  
x=180°90°  
=90°  
The value of x   is 90°  .
Hence option 2) is correct.
 
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