Questions
In the given figure, AP || BQ || CR. Prove that ar (AQC) = ar (PBR).
detailed solution
1
Since ∆ABQ and ∆PBQ lie on the same base BQ and are between the same parallels AP and BQ,
According to Theorem 9.2: Two triangles on the same base (or equal bases) and between the same parallels are equal in area.
Area (ΔABQ) = Area (ΔPBQ) ...(1)
Similarly, ∆BCQ and ∆BRQ lie on the same base BQ and are between the same parallels BQ and CR.
Area (ΔBCQ) = Area (ΔBRQ) ... (2)
On adding Equations (1) and (2), we obtain
Area (ΔABQ) + Area (ΔBCQ) = Area (ΔPBQ) + Area (ΔBRQ)
Hence, Area (ΔAQC) = Area (ΔPBR) is proved.
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