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In the given figure below, the velocity versus time graph is shown for a particle of mass 1 kg
Match the column I and column II mark the correct option from the given codes
Column I Column II
A) Work done is maximum P) t =1s to t = 2s
B) Average power is maximum      Q) from t = 3s to t = 5s
C) Work done is zero R) from t = 2 s to t = 3s
D) Force is maximum       S) t = 0 to t = 1s

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$A \to Q; B \to P; C \to R; D \to R S$

$A \to Q; B \to R; C \to P; D \to R S$

$A \to R S; B \to R; C \to Q; D \to P$

$A \to R; B \to P; C \to Q; D \to R S$

answer is C.

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Detailed Solution

Work done maximum

$\Rightarrow W = {(Δ K E)}_{\max}$

$Avg power = \frac{∆ KE}{t}$

$W = 0 \Rightarrow s l o p e = 0$

$F = \max \Rightarrow F = m (s l o p e)$

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