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In the given figure, find the value of x, if AB||CD.

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3 m

4 m

8 m

answer is A.

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Detailed Solution

Given the figure,
Question Image

In given figure AB II CD And line

DO

and

CO

cut side

AB

and

CD

D, A, C

and

B

∠ OCD = ∠ OBA

....... (corresponding angle )

∠ ODC = ∠ OAB

...... (corresponding angle )

∠ COD = AOB

....... (Common angle )

ΔCOD

and

ΔBOA

are similar triangle By AAA
Then

\frac{DO}{AO} = \frac{CD}{AB}

\Rightarrow \frac{6 + x}{x} = \frac{5.49}{1.83}

\Rightarrow 6 + x = 3 x

\Rightarrow 3 x - x = 6

\Rightarrow x = 3

Therefore,

x = 3

.
Hence option 1 is the answer.

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