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Q.

In the given figure if i1 = 3sin ωt and i2 = 4cosωt, then i3 is :

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a

5 sin (ωt+ 53°)

b

5 cos (ωt+ 53°)

c

5 sin (ωt+ 45°)

d

5 sin (ωt+ 37°)

answer is A.

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Detailed Solution

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i3=i1+i2=535sinωt+45cosωt   =5sinωt.cos53o+cosωt.sin53o   =5 sinωt+53o

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