In the given figure, if$\angle ABD=106°$ and$\angle ACF=118°$ . Then value of $\angle A$ is

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Given $\angle ABD=106°$

$\angle ACF=118°$

$\angle ACB+\angle ACF=180°$ (linear pair)

$\angle ACB+118°=180°$

$\angle ACB=180°-118$

$\angle ACB=62°$

Exterior angle is equal to sum of its opposite interior angles.

$\angle A+\angle ACB=\angle ABD$

$\angle A+62°=106°$

$\angle A=106°-62°$

$\angle A=44°$