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In the given figure, P is 300 km eastward of O and Q is 400 kms North of O, R is exactly in the middle of Q and P. The distance between Q and R is

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250 kms

$250 \sqrt{2} k m s$

300 kms

350 kms

answer is A.

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Detailed Solution

${QP}^{2} {= OQ}^{2} {+ OP}^{2}$

$QP = \sqrt{{OQ}^{2} {+ OP}^{2}}$

$QP = \sqrt{400^{2} {+ 300}^{2}}$

$QP = \sqrt{500^{2}} = 500$

$QR = \frac{Q P}{2} = \frac{500}{2} = 250 k m s$

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