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In the given meter bridge diagram, the balancing length is 65 cm when P = 5Ω. Now when an unknown resistance X is connected with P in series then balancing length becomes 70 cm. The value of X is nearly equal to

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0.6Ω

1.3Ω

2.8Ω

3.2Ω

answer is B.

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Detailed Solution

$\frac{P}{I} = \frac{R}{100 - l} \Rightarrow R = \frac{35}{13}$
New resistance $P^{'} = (P + x) \Rightarrow P^{'} = (5 + x)$
$\frac{P^{'}}{70} = \frac{R}{30} \Rightarrow P^{'} = 6 .3 Ω$

$\Rightarrow 5 + x = 6 .3 \Rightarrow x = 1 .3 Ω$

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