In the given reaction

            

 The number of $\pi$ Electrons present in the product ‘P’ is ______

The given reaction shows cyclohexanone treated with a strong base (OH⁻), followed by heating. This is a classic example of the aldol condensation (specifically, a self-aldol condensation), leading to an α,β-unsaturated ketone as the major product.

Stepwise Solution:

• The base (OH⁻) abstracts an alpha proton from cyclohexanone, resulting in enolate formation.
• Two cyclohexanone molecules react: one acts as a nucleophile, the other as an electrophile.
• The aldol product (β-hydroxyketone) undergoes dehydration upon heating, forming cyclohex-2-en-1-one.

The structure of the main product ('P') is cyclohex-2-en-1-one, which contains a conjugated double bond (C=C) and a carbonyl group (C=O).

Calculation of π Electrons:

• C=C double bond: 2 π electrons
• C=O double bond: 2 π electrons

Total π electrons in the product = 2 (from C=C) + 2 (from C=O) = 4 π electrons

Answer: The number of π electrons present in the product ‘P’ is 4.