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In the given reaction, $H_{2} (g) \to 2 H (g); ΔH = 435 .0 {kJ mol}^{- 1}$ . The enthalpy change in this process is known as

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enthalpy of vaporisation

enthalpy of dissociation

enthalpy of sublimation

enthalpy of association

answer is A.

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enthalpy change taking place when one mole of compound dissociates into its elements by homolytic fission is known as bond enthalpy

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