In the given right-angled triangle ABC, ∠B = 90°. Find the value of x.

In $\Delta ABC, \angle B=90°$

$A{B}^2+B{C}^2=A{C}^2$ (By Pythagoras property)

$5^2+{(x-3)}^2={(x+2)}^2$

$25+x^2+9-6x=x^2+4+4x$

$-6x-4x=4-9-25$

$-10x=-30$

$x=3$

Hence, the required value of $x=3$