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In the given system a capacitor of plate area A is charged upto charge q. The mass of each plate is $m_{2} .$ The lower plate is rigidly fixed. Find the value of $m_{1}$ so that the system is in equilibrium.

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$m_{2} + \frac{q^{2}}{ε_{0} A g}$

$m_{2}$

$\frac{q^{2}}{2 A ε_{0} g} + m_{2}$

None of these

answer is C.

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Detailed Solution

For upper plate, we have $T = F_{e} + m_{2} g$

For $m_{1}$ , we have $T = m_{1} g$

On equating above two equations, we get $m_{1} g = \frac{q^{2}}{2 A ε_{0}} + m_{2} g$

$m_{1} = \frac{q^{2}}{2 A ε_{0} g} + m_{2}$

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