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In the given (V - T) diagram, what is the relation between pressures $P_{1} a n d P_{2} ?$

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$P_{2} < P_{1}$

Cannot be predicted

$P_{2} = P_{1}$

$P_{2} > P_{1}$

answer is A.

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Detailed Solution

According to ideal gas equation

PV = nRT

Or $V = \frac{n R T}{P}$

For an isobaric process, P = constant and $V \propto T$

Therefore, V - T graph is a straight line passing through origin. Slope of this line is inversely proportional to P.

In the given figure,

${(S l o p e)}_{2} > {(S l o p e)}_{1} ∴ P_{2} < P_{1}$

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