In the Hofmann bromamide degradation reaction, the number of moles of NaOH and Br2 used per mole of amine produced are:

Four moles of NaOH and two moles of Br 2 .

Four moles of NaOH and two moles of Br 2 .

One mole of NaOH and one mole of Br 2 .

Four moles of NaOH and two moles of Br 2 .

Two moles of NaOH and two moles of Br 2 .

Four moles of NaOH and one mole of Br 2 .

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In the Hofmann bromamide degradation reaction, the number of moles of NaOH and Br₂ used per mole of amine produced are:

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One mole of NaOH and one mole of Br₂.

Four moles of NaOH and two moles of Br₂.

Two moles of NaOH and two moles of Br₂.

Four moles of NaOH and one mole of Br₂.

answer is B.

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$\begin{array}{l} RC O {NH}_{2} + {Br}_{2} + 4 NaOH \\ ↓ \\ R - {NH}_{2} + {Na}_{2} C O_{3} + 2 NaBr + 2 H_{2} O \end{array}$

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