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Q.

In the horizontal smooth tube there is a circular bend of radius r=10m located in the vertical plane. What is the minimum speed (in m/s)to be given to thin flexible rope of length L=4πr  horizontal position so that it just crosses the circular bend and again become horizontal? Consider the radius of the loop r is much larger than the radii of the pipe and rope and the rope was initially in left horizontal section. [Take g=10m/s2]

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answer is 10.

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Detailed Solution

The minimum speed of the loop is reached when the center of mass of the part of the rope having a mass  m'=m2πrl is raised to the height r .  12mv2=m'gr  or  vmin=2rgπL

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