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Q.

In the interval [0, 1] the function x25(1-x)75 takes a maximum value at

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a

x=0

b

x=14

c

x=12

d

x=1

answer is A.

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Detailed Solution

fx=x251-x75 logfx=25logx+75log1-x fIxf(x)=25x+751-x-1

fx is min or max

fIx=0 25x=751-x 1-x=3x1=4x x=1/4

fx is max at x=1/4

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