In the isoelectronic species the ionic radii A° of N-3,O-2,F-are respectively given by

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In the isoelectronic species the ionic radii $(A^{°})$ of $N^{- 3}, O^{- 2}, F^{-}$ are respectively given by

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1.36, 1.71, 1.40

1.71, 1.40, 1.36

1.36, 1.40, 1.71

1.71, 1.36, 1.40

answer is D.

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Detailed Solution

For the iso electronic species $N^{- 3}, O^{- 2}, F^{-},$ more the negative charge Present on the ion. Hence they have more ionic radii.

For $N^{- 3}, O^{- 2}, F^{-},$ ionic radii's $1.71, 1.4, 1.36$

Note: If the net charge on anion increases then the size will increase for isoelectronic species.

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