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In the last second of free fall, a body covered 3/4 of its total path. Then the height from which the body is released will be

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4.9 m

9.8 m

19.6 m

39.2 m

answer is C.

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Detailed Solution

$h = 0 \times t + \frac{1}{2} \times 10 \times {t^2}..................(1)$
$\frac{3}{4}h = \left[ {0 + 10 \times (t - 1)} \right](t - 1) + \frac{1}{2} \times 10 \times {(t - 1)^2}............(2)$

Solving both the equations, we get, t=2 sec and h= 20 m
If we take the value of g = 9.8 m/s² , h= 19.6 m

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