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I is increasing and Q is increasing.

I is increasing and Q is decreasing.

I is decreasing and Q is increasing.

I is decreasing and Q is decreasing.

answer is B.

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Detailed Solution

Given capacitor is fully charged and after t = 0, the charge on capacitor is given by Q = $Q_{0} \cos ω t .$ Also current i = - $\frac{d q}{d t} = \frac{Q_{0}}{\sqrt{L C}} \sin ω t .$ Therefore charge is getting reduced and current is increasing.

Energy of capacitor is decreasing resulting in increase in the energy of inductor.

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