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In the network shown, when switch S is open, power dissipated in the circuit is 15 W. When S is closed, power dissipated in the circuit is 20 W. The $R_{3}$ is

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$2.12 Ω$

$1.67 Ω$

$4.6 Ω$

$5 Ω$

answer is C.

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Detailed Solution

$R_{1} + R_{2} + R_{3} = \frac{{(10)}^{2}}{15} and R_{1} + R_{2} = \frac{{(10)}^{2}}{20}$

$∴ R_{3} = (\frac{100}{15} - \frac{100}{20}) Ω = 1.67 Ω$

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