In the nuclear reaction $_{1} H^{2} +_{1} H^{2} \to_{0} n^{1} +_{2} H e^{3}$ , if the binding energy of deuteron is 2.23MeV and the Q value of reaction is 3.27 MeV then the binding energy of ₂He³ is …...

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1.19 MeV

3.27 MeV

4.46 MeV

7.73 MeV

answer is B.

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Detailed Solution

$_{1} H^{2} +_{1} H^{2} \to_{0} n^{1} +_{2} H e^{3}$
Binding energy of 2 deuterons = 2x2.23=4.46 MeV
Given Q-Value = 3.27 MeV
Binding Energy of 2He3=4.46+3.27 = 7.73 MeV

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