Q.

In the nuclear reaction  1H2+1H22He3+0n1 If the mass of the deuterium atom=2.014741 amu, mass of  2He3 atom =3.016977 amu and mass of neutron=1.008987 amu, then the Q value of the reaction is nearly.

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a

2.45 MeV

b

3.27 MeV

c

0.00352MeV

d

0.82 MeV

answer is B.

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Detailed Solution

Q=mrmpC2

mr=2×2.014741amu

mp=(3.016977+1.008987)amu

Δm=4.0294824.025964=0.003518amu

Q=0.003518×931MeV=3.27MeV

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