In the $P-V$  graph of ideal gas given below the work done in complete cycle $ABCD$ in $J$  is…  
$(1L-atm=101.3J)$

 

 $A\to B =P\Delta V=-15(6-2)=-60litatm$   
$B\to C$  Since volume in constant no work is done
$C\to D P\Delta V=6(6-2)=+24lit.atm$  
$D\to A$   Volume is constant,w=0
Total work done  $=-60+24 =-36\times 101.3J=-3646.8J$