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In the photoelectric experiment, if we use a monochromatic light, the I – V curve is as shown. If work function of the metal is 2eV, estimate the power (in watt) of light used. (Assume efficiency of photo emission $= 10^{- 3} %,$ i.e. number of photoelectrons emitted are $10^{- 3} %$ of number of photons incident on metal.)

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answer is 7.

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Detailed Solution

$h v = w + k_{\max} = 7 e V$

Saturation current $= 10 \times 10^{- 6} A = \frac{η P}{h v} e$

$= \frac{10^{- 5} P}{7 \times e} e (η i s p h o t o e m i s s i o n e f f i c i e n c y)$

$∴ P = 7 W$ .

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