In the presence of charges in the space, line integral of the electric field ∫E→⋅dl→ for a closed path as shown, is carried out

In an electric field ΔV = − ∫ E → ⋅ d l → In an electric field of electrostatic origin ,for a closed loop, Δ V = 0

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In the presence of charges in the space, line integral of the electric field $\int \vec{E} \cdot d \vec{l}$ for a closed path as shown, is carried out

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The value of the integral is Independent of the shape of the path

The value of the integral is independent of where charges may be located relative to the path

The value of the integral is always constant

The value of the integral is always negative

answer is A, B, C.

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In an electric field $ΔV = - \int \vec{E} \cdot d \vec{l}$

In an electric field of electrostatic origin ,for a closed loop, $Δ V = 0$

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