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Q.

In the propagation of electromagnetic waves the phase difference between the $\bar{E} and \bar{B}$ is

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a

$90^{o}$

b

$45^{o}$

c

$180^{o}$

d

$0^{o}$

answer is A.

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Detailed Solution

A plane which contains $\vec{E}$ and the propagation direction is called the plane of polarization.

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