In the reaction : Pb₃O₄ + 8HCl → 3PbCl₂ + Cl₂ + 4H₂O, the oxidation state of lead changes from

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+2 to zero

+4 to +2

+2 to +4

+4 to zero

answer is C.

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Detailed Solution

In the given reaction,

Pb₃O₄ + 8HCl → 3PbCl₂ + Cl₂ + 4H₂O

Pb₃O₄is a mixture of PbO.PbO₂ where oxidation state of Pb in PbO is +2 and in PbO₂ is +4. In the product side, oxidation state of Pb in PbCl₂ is +2. Hence, there is change in oxidation state of Pb from +4 to +2.

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