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In the reaction :

, the oxidising agent is

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${MnO}_{4}^{-}$

$C_{2} O_{4}^{- 2}$

Mn²⁺

H⁺

answer is A.

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Detailed Solution

\mathop {Mn}\limits^{ + 7} O_4^ - + \mathop {{C_2}}\limits^{ + 3} O_4^{2 - } + {\text{ }}{H^ + } \to {\text{ }}\mathop {M{n^{2 + }}}\limits^{ + 2} + {\text{ }}\mathop {C{O_2}}\limits^{ + 4} + {\text{ }}{H_2}O

show decrease in oxidation number
it is an oxidizing agent

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