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Q.

In the reaction 2PCl5 PCl4+ + PCl6   the change in hybridization is from

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a

 sp3d to sp3 and sp3d2

b

sp3d to sp2 and sp3

c

sp3d to sp3d2 and sp3d3

d

sp3d2 to sp3 and sp3d

answer is A.

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Detailed Solution

Number of electron pairs = 

\frac{1}{2}(V + M - C + A)

V = Group number of central atom

M = Number of monovalent groups directly attached to central atom

C = overall positive  charge of the species

A = Overall negative charge of the species.

Number of bond pairs = Number of atoms directly attached to central atom

"Bond Pairs" according to VSEPR theory can be single bond, double b and (or) triple bond

Number of lone pairs = (Number of electron pairs-Number of bond pairs)

speciesElectron pairsHybridisation
PCl5
\frac{1}{2}(5 + 5 - 0 + 0)
 sp3d
PCl6-
\frac{1}{2}(5 + 6 - 0 + 1)
 sp3d2
PCl4+
\frac{1}{2}(5 + 4 - 1 + 0)
sp3

                     

 

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