In the reaction 92X234→87Y218 how many α− particles and β− particles are emitted?

Nα=Ax−Ay4=234−2184=492=87+2×4−Nβ⇒Nβ=3

In the reaction 92X234→87Y218 how many α− particles and β− particles are emitted?

Nα=Ax−Ay4=234−2184=492=87+2×4−Nβ⇒Nβ=3

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In the reaction $_{92} X^{234} \to_{87} Y^{218}$ how many $α -$ particles and $β -$ particles are emitted?

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4 and 7

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answer is C.

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Detailed Solution

$N_{α} = \frac{A_{x} - A_{y}}{4} = \frac{234 - 218}{4} = 4$

$92 = 87 + 2 \times 4 - N_{β}$

$\Rightarrow N_{β} = 3$

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In the reaction 92X234→87Y218 how many α− particles and β− particles are emitted?

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In the reaction $_{92} X^{234} \to_{87} Y^{218}$ how many $α -$ particles and $β -$ particles are emitted?