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In the reaction A →2B, the concentration of A falls from 1.0M to 0.9982M in one minute what is the rate in moles litre^-1 sec^-1

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3.6 × 10^–3

6.0 × 10^–5

1.8 × 10^–3

3.0 × 10^–5

answer is B.

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Detailed Solution

$Rate = \frac{d [A]}{dt} = \frac{1 - 0.9982}{60} = 3 \times 10^{- 5}$

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