In the reaction $A\to 2B$ , the concentration of A falls from 1.0M to 0.88M in one minute what is the rate in moles ${\text{litre}}^{-\text{1}}{\text{sec}}^{-\text{1}}$

For the reaction

$A\to 2B$

Given, $\left[\text{A}\right]=1.0 \text{M}\text{to 0}\text{.88 M}$

Time= 1 minute

Rate=?

$\text{rate=}\frac{\text{dC}}{\text{dt}}$

Where,

$\text{dC}$ = Change in concentration

dt= time taken for the change

$\text{rate=}\frac{(1-0.88)}{1\text{min}}$

$\text{rate=}\frac{0.12}{60}$

$=\frac{1}{5}\times {10}^{-2}$

$=2\times {10}^{-3}$