In the reaction : ${Al}_{2} {({SO}_{4})}_{3} \cdot 18 H_{2} O \cdot \to_{- 18 H_{2} O}^{h e a t} A \overset{800^{\circ} C}{⟶} B + C$ . The product A, B and C are respectively

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${Al}_{2} {({SO}_{4})}_{3}, {Al}_{2} O_{3}, {SO}_{2}$

${Al}_{2} {({SO}_{4})}_{3}, {Al}_{2} O_{3}, {SO}_{3}$

${Al}_{2} {SO}_{4}, {Al}_{2} O_{3}, {SO}_{3}$

${Al}_{2} O_{3}, {Al}_{2} {({SO}_{4})}_{3}, {SO}_{3}$

answer is A.

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Detailed Solution

The compound decomposes to alumina and sulfur trioxide when heated between 580 and 900 °C.

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